Solving 3^(x-5) = 9 A Step-by-Step Guide

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Hey math enthusiasts! Ever stumbled upon an equation that looks intimidating at first glance but turns out to be surprisingly elegant? Today, we're going to dissect one such equation: 3x−5=93^{x-5} = 9. This isn't just about finding the value of 'x'; it's about understanding the underlying principles of exponential equations and how to tackle them with confidence. So, buckle up, and let's dive in!

Understanding the Basics of Exponential Equations

Before we jump into solving 3x−5=93^{x-5} = 9, let's solidify our understanding of what exponential equations are. In essence, an exponential equation is an equation where the variable appears in the exponent. The general form can be represented as af(x)=ba^{f(x)} = b, where 'a' is the base, 'f(x)' is the exponent (a function of x), and 'b' is a constant. Our equation, 3x−5=93^{x-5} = 9, perfectly fits this description. Here, the base is 3, the exponent is (x-5), and the constant is 9. The key to solving exponential equations lies in manipulating them to a form where we can directly compare the exponents. We often achieve this by expressing both sides of the equation with the same base. This brings us to a crucial property: if am=ana^m = a^n, then m = n, provided that 'a' is a positive number not equal to 1. This property is the cornerstone of our approach to solving 3x−5=93^{x-5} = 9. We need to rewrite the equation so that both sides have the same base. In our case, we can express 9 as a power of 3, which simplifies the equation significantly. Understanding these foundational concepts is crucial. Exponential equations pop up everywhere, from compound interest calculations to population growth models. Mastering them opens doors to solving real-world problems and understanding complex phenomena. So, let's keep these principles in mind as we move forward and tackle our specific equation.

The Strategy: Expressing Both Sides with the Same Base

The core strategy for solving our equation, 3x−5=93^{x-5} = 9, and many other exponential equations, revolves around the idea of expressing both sides with the same base. Why is this so important? Well, when we have the same base on both sides of the equation, we can directly equate the exponents, simplifying the problem immensely. In our case, the left side of the equation already has a base of 3: 3x−53^{x-5}. The right side, however, is the constant 9. Can we express 9 as a power of 3? Absolutely! We know that 9=329 = 3^2. This simple transformation is the key to unlocking the solution. By rewriting 9 as 323^2, our equation now becomes 3x−5=323^{x-5} = 3^2. Notice how both sides now have the same base, which is 3. This is a pivotal moment in our problem-solving journey. Now that we have the same base on both sides, we can apply the fundamental property of exponential equations: if am=ana^m = a^n, then m = n. In our case, this means that if 3x−5=323^{x-5} = 3^2, then x - 5 = 2. We've successfully transformed the exponential equation into a simple linear equation, which is much easier to solve. This step-by-step approach – identifying the common base, rewriting the equation, and equating the exponents – is a powerful technique that can be applied to a wide range of exponential equations. So, remember this strategy; it's your secret weapon for tackling these types of problems. Now, let's move on to the next step and solve the resulting linear equation.

Solving the Linear Equation: x - 5 = 2

Having successfully transformed our exponential equation 3x−5=93^{x-5} = 9 into the linear equation x - 5 = 2, we're now in familiar territory. Solving linear equations is a fundamental skill in algebra, and this particular equation is quite straightforward. Our goal is to isolate 'x' on one side of the equation. To do this, we need to get rid of the -5 on the left side. The opposite operation of subtraction is addition, so we'll add 5 to both sides of the equation. This maintains the balance and ensures that the equation remains true. Adding 5 to both sides of x - 5 = 2 gives us: x - 5 + 5 = 2 + 5. Simplifying this, we get x = 7. And there we have it! The solution to our equation is x = 7. It's always a good practice to verify our solution to ensure accuracy. We can do this by substituting x = 7 back into the original equation, 3x−5=93^{x-5} = 9. Substituting x = 7, we get 37−5=323^{7-5} = 3^2, which equals 9. This confirms that our solution, x = 7, is indeed correct. This process highlights the importance of not only solving the equation but also verifying the solution. It's a crucial step in problem-solving that helps prevent errors and builds confidence in our results. So, remember to always double-check your work, especially in exams or when dealing with complex problems. Now that we've found the solution, let's reflect on the entire process and discuss some common pitfalls to avoid.

Verification and Final Answer

We've arrived at a potential solution for our equation, x = 7. But, as any good mathematician knows, the job isn't quite done until we've verified our answer. Verification is a crucial step in the problem-solving process, ensuring that our solution is accurate and that we haven't made any errors along the way. To verify our solution, we substitute x = 7 back into the original equation, 3x−5=93^{x-5} = 9. This gives us 37−5=93^{7-5} = 9. Simplifying the exponent, we have 32=93^2 = 9. And indeed, 323^2 is equal to 9. This confirms that our solution, x = 7, is correct. It's like a little victory dance when the verification works out! This step provides not only assurance but also a deeper understanding of the equation itself. By plugging the solution back in, we're reinforcing the connection between the equation and its solution. Now that we've confidently verified our answer, we can state our final answer: x = 7. This is the value of x that satisfies the equation 3x−5=93^{x-5} = 9. We've successfully navigated the world of exponential equations, applied key strategies, and arrived at a definitive solution. But before we conclude, let's take a moment to reflect on the common mistakes people make when solving equations like this and how to avoid them.

Common Pitfalls and How to Avoid Them

Solving exponential equations can be tricky, and it's easy to stumble if you're not careful. Let's highlight some common pitfalls that students often encounter and how to sidestep them. One frequent mistake is forgetting the fundamental property of exponential equations: if am=ana^m = a^n, then m = n. People might get caught up in the algebraic manipulations and lose sight of this core principle. To avoid this, always remember to express both sides of the equation with the same base before equating the exponents. Another common error is mishandling negative exponents or fractional exponents. These can be confusing, and it's crucial to have a solid understanding of what they represent. For instance, a negative exponent indicates a reciprocal (a−n=1/ana^{-n} = 1/a^n), and a fractional exponent represents a root (a1/n=throotnaa^{1/n} = throot{n}{a}). Reviewing these exponent rules regularly can help prevent mistakes. Additionally, careless arithmetic errors can derail the solution process. A simple mistake in adding or subtracting can lead to an incorrect answer. This is where verification comes in handy. Always plug your solution back into the original equation to check for accuracy. If the equation doesn't hold true, you know there's an error somewhere. Lastly, some students struggle with simplifying expressions before attempting to solve the equation. Look for opportunities to simplify both sides of the equation before diving into more complex manipulations. This can make the problem much more manageable. By being aware of these common pitfalls and actively working to avoid them, you'll become a more confident and proficient problem-solver in the realm of exponential equations. Now, let's wrap things up with a final summary of our approach.

Conclusion: Mastering Exponential Equations

Alright, guys, we've journeyed through the process of solving the exponential equation 3x−5=93^{x-5} = 9, and hopefully, you've gained some valuable insights along the way. Remember, the key to conquering these types of equations lies in understanding the fundamental principles and applying a systematic approach. We started by recognizing that this was an exponential equation, where the variable 'x' was in the exponent. We then identified the core strategy: expressing both sides of the equation with the same base. This allowed us to transform the equation into a simpler form. We successfully rewrote 9 as 323^2, giving us 3x−5=323^{x-5} = 3^2. This crucial step enabled us to equate the exponents, leading to the linear equation x - 5 = 2. Solving this linear equation was straightforward: we added 5 to both sides, isolating 'x' and finding the solution x = 7. But we didn't stop there! We emphasized the importance of verification, plugging x = 7 back into the original equation to confirm its validity. This step not only ensures accuracy but also deepens our understanding of the equation. Finally, we discussed common pitfalls to avoid, such as forgetting the fundamental property of exponential equations, mishandling exponents, making arithmetic errors, and neglecting to simplify expressions. By being mindful of these potential traps, you can approach exponential equations with confidence and precision. So, keep practicing, keep exploring, and remember that mastering exponential equations is a valuable skill that will serve you well in various areas of mathematics and beyond. You've got this!